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Subject: Re: A pondering idea... [a more clear {hopefully} example]

Author: Uri Blass

Date: 09:08:37 09/28/01

Go up one level in this thread


On September 28, 2001 at 10:55:46, Robert Hyatt wrote:

>On September 28, 2001 at 00:58:15, Dann Corbit wrote:
>
>>On September 27, 2001 at 23:44:19, Robert Hyatt wrote:
>>
>>>On September 27, 2001 at 19:05:43, Dann Corbit wrote:
>>>
>>>>On September 27, 2001 at 17:48:32, Peter Fendrich wrote:
>>>>[snip]
>>>>>Yes, I buy all that. My intention was to oppose to the "it's impossible"
>>>>>statement. You are talking about some general case. There is no reason why each
>>>>>move has to be 20% because the first one is. That's why I'm talking about
>>>>>isolating cases where the other move might be better. Another question is what
>>>>>happens if the ponder move has only 10% or 5% probability.
>>>>>I have no proofs that these cases are possible to identify but I'm still open
>>>>>for it, until I know better...
>>>>
>>>>Also, it does not have to be either/or.
>>>>
>>>>We could ponder the root for 1/2 of the extrapolated opponent time slice, and at
>>>>that point, change to the pm and ponder that.
>>>>
>>>>It seems to me that there are many possibilities.
>>>>
>>>>Something that is puzzling me...
>>>>If one move is really much better than the others, then we would think that it
>>>>would fail high, re-search, and gobble most of the time anyway.  If that does
>>>>not happen, then some of the alternatives must be pretty good.
>>>>
>>>>So, why does pondering root yield only a 2% gain, and pondering the pm give an
>>>>enormous one?
>>>>
>>>>It still does not make sense to me.
>>>>
>>>>I guess I'm just having a hard time understanding why it is so much better to
>>>>ponder the pm instead of the root.
>>>
>>>If by "root" you mean the position _before_ any opponent move, then the reason
>>>is obvious...  you will spread your time over N moves, which means that when
>>>the opponent moves, you will have looked at the _right_ move only 1/N of the
>>>time.  You still have a long time to search to meet the target time for this
>>>search.
>>
>>By the root, I mean "the root move for the opponent -- after I have made my move
>>but before the opponent returns the response.  In other words, the opponent's
>>current position.
>>
>>If the search is so even that time is distributed over N moves, then the chance
>>of picking the right one is only 1/N anyway.
>>
>>If two or three moves are far better than the others, then most of the time will
>>have been spent searching them.
>
>This is not correct.  We are using alpha/beta remember.  The _best_ move will
>consume about 75% of the total search time.  The next best move will take a
>tiny fraction of that to prove it is worse, even if it is only .01 worse.

I believe that the truth is in the middle.
blunders are often considered for less time when moves that are worse by 0.01
pawn considered for more time in most of the cases but it is only an average
rule and not a general rule.

Uri



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