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Subject: Re: Cabablilities of a SEE

Author: Paul

Date: 07:11:36 10/04/01

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On October 04, 2001 at 07:03:14, Tim Foden wrote:

>Hi All,
>
>I decided that I would add a 2nd SEE to GLC to check whether GLC's SEE was
>working.  I actually ported GCP's Sjeng SEE (that was posted to the forum a
>while ago).
>
>Both SEE routines now agree in most curcumstances, but one's like the following
>have cropped up (where they disagree):
>
>[D]5rk1/1pp2R1p/p1pb4/6q1/3P1p2/2P4r/PP1BQ1P1/5RKN w - - 2 0
>
>This can be evaluated in 2 ways...
>
>(1) BxP (+1000) BxB (-3500) R1xB (+3500) QxR (-5500) RxQ (+10000) RxR (-5500)
>.........+1000.......-2500........+1000.......-4500........+5500...........0
>
>>>> value = 0
>
>(2) BxP (+1000) BxB (-3500) R7xB (+3500) RxR (-5500) RxR (+5500) QxR (-5500)
>.........+1000.......-2500........+1000.......-4500.......+1000.......-4500
>
>>>> value = -2500
>
>So... on to the questions:
>
>a) Does anyone's SEE do anything intelligent in these cases?
>
>b) Is one of these right, and the other wrong?  If so, which one?
>
>c) Do we actually care, as long as the SEE works in the majority of cases?
>
>Cheers, Tim.

I haven't studied SEE yet, but shouldn't (2) also result in a value = 0, since
you don't have to take the pawn being white? I mean, you start with a value of
0, right?

Paul



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