Author: Robert Hyatt
Date: 07:50:39 02/07/02
Go up one level in this thread
On February 07, 2002 at 05:04:56, Ralf Elvsén wrote: >On February 06, 2002 at 22:47:08, Robert Hyatt wrote: > >>On February 06, 2002 at 20:05:18, Eran wrote: >> >>>On February 06, 2002 at 18:12:11, Dann Corbit wrote: >>> >>>>[D]4k3/Q3p1Q1/1Q5B/Q1QN1NQ1/4QQ2/B2Q4/8/2R1KR2 w - - acd 4; acn 29; acs 0; bm >>>>Nc7# Nd6# Nf6# Q5g6# Q7g6# Qaa4# Qab5# Qaxe7# Qbb5# Qbb8# Qbc6# Qbg6# Qc8# Qcb5# >>>>Qcc6# Qcxe7# Qd8# Qdb5# Qea4# Qexe7# Qf8# Qfb8# Qg5xe7# Qg7xe7# Qg8# Qh5#; ce >>>>32766; dm 1; pv Nd6#; >>>> >>>>I have found that some programs crash, and others think for minutes on this mate >>>>in 1. >>> >>>Your position is not realistic, because nine White Queen pieces are on the >>>board. In fact, every game each side cannot have more than eight pawns. If a >>>player promotes all his/her eight pawns, there will be no more than eight Queen >>>pieces on his/her side. Therefore, your position is baloney! It never happened. >>> >>>Eran >> >> >>What about the _original_ queen? 8 pawn promotions + one original queen >>= nine queens? > >Nine queens are possible, but not at the same time as two >dark-squared bishops :) ] Yes. But I was responding to this: >>>board. In fact, every game each side cannot have more than eight pawns. If a >>>player promotes all his/her eight pawns, there will be no more than eight Queen >>>pieces on his/her side. Therefore, your position is baloney! It never happened. Which says "every game". And that is certainly false. In the given position, you are right of course...
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