Author: Ratko V Tomic
Date: 13:12:49 04/26/02
Go up one level in this thread
>I presume you mean +- 1/sqrt(N) ? > >>From that you can get the >>upper and lower values for probabilities (normalized >>scores). I was using +/-sqrt(N) for absolute error. The relative (normalized to N) error is then 1/sqrt(N), as implied in my next sentence.
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