Author: Dann Corbit
Date: 11:05:45 12/24/03
Go up one level in this thread
On December 24, 2003 at 06:01:58, Reinhard Scharnagl wrote: >On December 24, 2003 at 00:54:50, Russell Reagan wrote: > >>On December 23, 2003 at 23:58:19, Reinhard Scharnagl wrote: >> >>>you are describing just the big translation table, I have spoken of. >>> >>>I will try to explain the nature of a solution I would like to have >>>(which is still not complete and in devlopment). >>> >>>Suppose the castling rigths are the following bits: bwl, bwr, bbl, bbr. >>> >>>a) if both kings are at original place, >>> encode Kw = kb = (bwl, bwr, 0, bbl, bbr, 0) >>>b) if only the white king is at original place, >>> 1) O-O only -> place him immediately over or under the black king >>> 2) O-O-O only -> place him immediately right or left to the black king >>> 3) both castlings -> ... still no idea, sorry >>>c) if only the black king is at original place, >>> 1) O-O only -> place him immediately NW or SE the white king >>> 2) O-O-O only -> place him immediately NE or SW to the white king >>> 3) both castlings -> ... still no idea, sorry >>> >>>That this moment is the direction I am thinking of a solution. >> >>Why do you only use the relative locations of the two kings? Instead of using >>north, south, east, west, and combinations of those, why not do it like this: >> >>If white king on a1 and black king on b1, then ... >>If white king on b1 and black king on c1, then ... >>If white king on c1 and black king on d1, then ... >>... >>If white king on e4 and black king on d5, then ... >>and so on... > >[...] > >That would have the form of a big cryptic translation table. I already have >mentioned, that such a solution would WORK. But I do not like it, because it >would not be a TRANSPARENT approach. > >Reinhard. A simple approach that also uses a table... Store the king positions in a table of two things, king postion bitmap and color: e.g. [D]8/8/8/8/8/8/8/K1k5 w - - becomes 0x5, 'W' Now, your board position for any set of two kings is just the index into this array. I think it is easy to understand.
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