Author: Michel Langeveld
Date: 09:13:41 01/27/04
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On January 26, 2004 at 23:50:38, Ed Trice wrote: >877,551,731 Oops ... I think this number is an answer that is 17 times overflowed and calculated with a program that uses 32bits. perft 1= 28 perft 2= 784 (is 28 x perft 1) perft 3= 25283 (is 32 x perft 2) perft 4= 809826 (is 32 x perft 3) perft 5= 28976137 (is 36 x perft 4) perft 6= 1027599562 (is 35 x perft 5) So if you put a gun at me and I have to guess an answer then I would say: perft 7 should be around: 1027599562 x 35 = 35.965.984.670. This is clearly bigger as what can be held within 32bits. I think we until perft 13-14 64bits can be used savely :-)
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