Computer Chess Club Archives


Search

Terms

Messages

Subject: Re: Outputting u64 word using printf?

Author: Eugene Nalimov

Date: 09:53:03 06/07/04

Go up one level in this thread


On June 07, 2004 at 12:06:48, Robert Hyatt wrote:

>On June 07, 2004 at 10:46:28, Uri Blass wrote:
>
>>On June 07, 2004 at 10:40:09, Fabien Letouzey wrote:
>>
>>>On June 07, 2004 at 10:36:58, Vincent Diepeveen wrote:
>>>
>>>>On June 07, 2004 at 10:30:50, Fabien Letouzey wrote:
>>>
>>>>r = 1<<36; // works for good compilers not for the rest
>>>
>>>Hm, my understanding is that first "1<<36" should be calculated (so it's 0 if
>>>sizeof(int) <= 4) and *then* cast into r's type (oops, too late).
>>>
>>>Fabien.
>>
>>A smart compiler should understand that 1<<36 cannot mean 0 because in that case
>>the programmer has no reason to write it in that way.
>>
>>The only logical meaning of 1<<36 is that it is a 64 bit number(espacially when
>>r is defined as a 64 bit number).
>>
>>Uri
>
>
>That would violate every C standard on the planet.  And break more programs than
>it would help.

Technically speaking it will not violate the standard. For this particular case
standard says "result is undefined", so compiler is free to replace ((long long)
(1 << 36)) by (((long long) 1) << 36). Of course it will create lot of other
problems, because you don't want such transformation for non-constant shift
amount.

Visual C 2005 emits warning for such shifts (guess who implemented it?) Some
other compilers emit similar warnings, too.

Thanks,
Eugene



This page took 0 seconds to execute

Last modified: Thu, 15 Apr 21 08:11:13 -0700

Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.