Author: José de Jesús García Ruvalcaba
Date: 05:04:55 06/10/04
Go up one level in this thread
On June 09, 2004 at 17:29:39, Dieter Buerssner wrote: >On June 09, 2004 at 13:24:54, José de Jesús García Ruvalcaba wrote: > >>On June 09, 2004 at 08:31:21, Peter Berger wrote: >> >>> >>>I enjoyed reading your posts but you generalized the problem too much IMHO. I >>>specifically referred to legal Swiss pairings only. I agree that there will >>>always be some way of pairing left but not one that also follows the much >>>stricter rules for Swiss pairings. >>> >>>If you have sufficient time you can look them up here: >>>http://www.fide.com/official/handbook.asp?level=C04 >>> >>>Peter >> >>Well, I did not generalise the problem too much. The FIDE swiss system rules are >>for sure strict, but they allow score brackets to be melted together if there is >>no other way of producing a pairing. Doing that succesvely until we get only one >>bracket (with n-3 rounds for n players that could easily happen according to the >>rules), we are in the situation I described. >> >>See >>http://www.fide.com/official/handbook.asp?level=C0401B >>B.3 is a relative pairing criterium. >> >>in C.13 of >>http://www.fide.com/official/handbook.asp?level=C0401C >>it is shown under which circumstances the last two score brackets are joined. > >The above two are for "Swiss tournament based on rating". The first of 3 Swiss >systems shown in the FIDE handbook. I had the impression, that typical Swiss >systems are played with the 2nd system shown (for example in Paderborn). But I >am not sure. Sorry, I did not make any reference to swiss system based on rating (participants at the WCCC do not have a reliable rating anyway). For those interested, the swiss system based on rating is described at http://www.fide.com/official/handbook.asp?level=C0403 but my previous links come from other sections. > >>And in 9.6 of >>http://www.fide.com/official/handbook.asp?level=C0402B > >Which is here > >>it is described how and in which direction the median score group is extended. > >I don't follow here. Can you explain it more carefully to me? To make a pairing, the absolute pairing rules must be always followed. As you point out a few lines down, one of them is never pair the same two players more than once. In order to achieve that anything is allowed, and the last resource (when nothing else works) is simply to melt two score brackets together. If you are making the pairings of the median group (the group that has m/2 points after m rounds) at the end, and are forced to melt it together with another one, it can be done in two directions: above and below, and the rules tell you exactly in which direction it has to be done. >In the above >example, there was no problem to pair round 3 with this system. Six players, n=6, there should be no problem to pair round 3=n-3, but it might not be posible to pair round 4=n-2 >I do not see any >rules, that look ahead to the next round. There are no rules that look ahead to the next round. >When you pair the 4th round, there is >no possible pairing, whatever you try. There probably most important rule, never >pair the same two players again, cannot be fullfilled. > >Regards, >Dieter The nightmare scenario from Peter is 11 rounds, and 13 or 14 players (d.h. n=14 and n-3=11 rounds). I for myself do not worry and am only happy that I am not the tournament director. José.
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