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Subject: Swiss Pairing question

Author: Robert Pope

Date: 13:32:55 06/16/99


It has been mentioned that the Swiss Pairing System is designed to find an
absolute winner in a tournament, but if not enough rounds are played, the
ordering of the lower places is not obvious.

Is it also true then that the pairing system also does the opposite at the same
time: finds the absolute worst-performing participant?  I don't mean this
question as an insult to any of the participants.  I was just wondering if this
is what the pairing system would do.

Also, from my understanding, the pairings try to pair opponents with the same
number of points.  What if most or all of the participants with the same point
score have already played each other?  Can they be paired a second time?




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