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Subject: Re: Calculation the number of positions of KQQKQQ and KQQKQP

Author: Michel Langeveld

Date: 01:32:48 09/04/99

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On September 03, 1999 at 15:07:09, Eugene Nalimov wrote:

>Using indixing schema that is currently used by TBGEN:
>
>KQQKQQ: 1,237,357,440 for each side to move. In this case, we need only one
>file, as black material is identical to white material. So, 1,237,357,440
>positions total.
>
>KQQKQP: wtm, 7,739,363,232 positions; btm, 8,024,974,680 positions (that is
>assuming you will not implement additional enumeration tables - that's possible,
>but will eat a lot of RAM). Total 15,764,337,912 positions.
>
>Eugene

Thanks for the answer I shall try to recalculate to the same number.
Maybe if I understand fully the theory I can help with some addition ideas.
I understand for KQQKQQ only one file is needed. I checked all my 4 piece
tablebases which is ... bytes total.

The amount of KQKQ.nbb, KRKR.nbb, KBKB.nbb, KPKP.nbb = 10.341.448. So these
files are not necesarry when the tablebasehit algorithm is adapted a little.
Amazing that this is 10.3/146.0 = 7% smaller.

I remember that you posted once in the Crafty mailinglist that you could drop
the total amount of bytes of the current set of .nbw and .nbb a slightly. Did
you refer to this above or something else? If something else then can you
explain it?

Michel Langeveld



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