Author: KarinsDad
Date: 06:17:26 09/04/99
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On September 03, 1999 at 18:46:52, Guido wrote: [snip] >You start to calculate KK, but I'm sorry to say that IMHO you are wrong :-)> >The number of positions should be 462, so evaluated:> > 1 x 4 = 1 x 33 = 33 white king in a1 > 3 x 6 = 3 x 58 = 174 white king in b1, c1, d1 > 3 x 9 = 3 x 55 = 165 white king in c2, d2, d3 > 3 x 9 = 3 x 30 = 90 white king in b2, c3, d4 > ---------- >Total 462 > >When white king is on the diagonal a1-h8, position for the black king are >reduced by symmetry. This always happens when a piece is added to a symmetrical >disposition of the preceding pieces in respect to this diagonal. Therefore if >the two kings are in a1 and c3, also the positions of the first queen are >reduced and so on. Yes, I understand this (nicely done). However, how does this affect the KK calculation when at least one pawn is there? Michel did not respond to my other post. KarinsDad :)
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