Author: Eugene Nalimov
Date: 19:18:12 03/09/00
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Is 8080 16-bit processor? It has 3 register pairs, each 16-bit wise, and there were operations that worked at those - addition, load, store. And z80 adds more 16-bit instructions - e.g subtraction with carry. On 68000 32-bit operations worked much slower than 16-bit operations, even for data on registers. Eugene On March 09, 2000 at 21:58:18, Tom Kerrigan wrote: >On March 09, 2000 at 21:03:17, Robert Hyatt wrote: > >>On March 09, 2000 at 17:34:47, Tom Kerrigan wrote: >> >>>On March 09, 2000 at 16:35:50, Pierre Bourget wrote: >>> >>>>>Never heard of an H7 or H8 processor. But many older chess programs were based >>>>>on Motorola 68000 series. 68000 is 16 bit, and 68020 is 32 bit. You can't just >>> >>>I believe the 68000 is 32-bit. It has a 24-bit address bus to reduce the >>>pincount. >>> >> >>He is right. the 6800 was 8 bit, the 68000 was 16 bit. the 020 was the >>first 32 bit member of the family... > >It depends on how you count bits. 16 bit data bus, 24 bit addresses, but any >comp org textbook will tell you that the 68000 has 8 32-bit general purpose data >registers and 8 32-bit address registers, and most of the instructions operated >on 32 bits at a time. > >If you really want to say a processor is n-bit when it has an n-bit data bus, be >my guest. But then most PCs become 64-bit, which I don't think you agree with. > >-Tom
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