Author: Tom Kerrigan
Date: 10:18:09 05/31/00
Go up one level in this thread
On May 31, 2000 at 10:48:50, Robert Hyatt wrote: >On May 31, 2000 at 01:10:52, Tom Kerrigan wrote: > >>On May 30, 2000 at 21:48:52, Robert Hyatt wrote: >> >>>>All I'm saying is that the numbers you gave (e.g. 25%) are (hash hits/hash >>>>probes) and not (hash hits/nodes). The latter is what's more important in this >>>>case. >>>> >>>>-Tom >>> >>> >>>That number would be meaningless. Of course you can't "hit" if you don't >>>"probe". Who would care? I only want to know what percentage of the time I >>>get a hit after doing a probe... which seems like the only reasonable measure >>>of anything. If a program probes in the q-search, those numbers would match >>>mine _exactly_ since in his case, probes == nodes. >> >>No, that number would NOT be meaningless. >> > >A number computed from dividing one independent value into another independent >value is meaningless. such a hit percentage would be useless unless you compare >two programs with identical q-searches. Because you are factoring in q-search >nodes which has absolutely nothing to do with the number of hash hits and >misses I get. Since I neither hit nor miss in the q-search. The optimization should not affect the number of nodes searched. So you ARE working with identical q-searches. And hash hits, for that matter. >>Sure, if you are trying to gague the effectiveness of a hash entry replacement >>scheme, it makes more sense to measure hits/probes. But in this case, "we" need >>to find out how many times the hash move can short-circuit move generation. So >>unless you don't generate moves in qsearch() either, the number is important. >> >>-Tom > > >Why? The question is does not generating moves save time? Not "does not >generating moves only in the normal search save time?" or not "does not >generating moves only in the q-search save time?" No, I think you need to go and read the original post. The question was, "how much faster will I be if I try hash table moves before generating the rest of the moves?" So if you only do hashing in "normal" search, then the question IS one of the latter (sort of). -Tom
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.