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Subject: Re: WMCCC pairings round 5 not in accordance with swiss system rules!

Author: Sylvain Renard

Date: 02:28:36 08/23/00

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>Can we be sure that it will be possible to do the pairing of the last round if
>we assume 2 conditions:
>
>1)All programs play against 9 different opponents
>2)All program play exactly 4 or 5 times with white.
>
>I believe it is possible but I do not know about a proof that say that it is
>possible in the worst case.
>
>Uri

  Hello,
Point n°1 is a basic rule of swiss system and should _always_ be respected
(if the game was really played, because if your opponent was not present
and comes back later in the tournament, you can be paired once more with him).
I really don't know if point n°2 is always possible. But with an even number
of rounds, I know that you cannot always play exactly half of the games
with white and the other half with black.
It is a good reason not to play 6, 8 or an even number of rounds (especially
with human french players :-)  because the guy who had 4 times black
and 2 times white wants to kill the arbiter at the end of the tournament :-)

 Best regards,
   Sylvain



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