Author: Ricardo Gibert
Date: 19:08:26 10/07/00
Go up one level in this thread
On October 07, 2000 at 15:16:17, Peter McKenzie wrote: >The position where the solution is most in doubt: > >[D]2k2K2/8/pp6/2p5/2P5/PP6/8/8 w - - > >The authors say that after 1.Ke8 Kc7 2.Ke7, black draws by 2...b5 with a >stalemate motif after 3.Ke6 b4 4.a4 Kb6. > >Of course white can vary, and they quote: 4.axb4 cxb4 5.Kd5 a5 6.Kc5 a4= > >Or: 2.a4 b5 which is supposed to be drawn too. > >I haven't checked these lines thoroughly, but quickly playing some of them vs my >program suggests they are probably correct. Certainly its possible there is a >mistake though. > >The other controversial positon: > >[D]8/1k6/p4p2/2p2P2/p1P2P2/2P5/P1K5/8 w - - > >Kc1 is analysed using the 'theory of corresponding squares', something I don't >really understand :-) I haven't analysed this one at all, I will just quote the >main variation: > >1.Kc1! Kc7 2.Kd1! Kd7 3.Ke1 Kc7 4.Kf2 Kd8 5.Ke2 Ke8 6.Kd3 Kd7 7.Ke3 Kd6 8.Ke4 >"(forcing the pawn to advance)" a3 9.Kd3 a5 10.Kc2! a4 "The posiiton on the >Q-side is blocked; a quadratic system with non-ambiguous rear (711) now >operates." Go figure! 11.Kc2! Ke7 12.Kd3 Kc6 13.Ke2 Kd6 14.Kf2 Kd7 15.Ke3 Ke7 >16.Kf3 and wins I played thru this using Fritz4, which instantly returns a draw score upon my playing 4.Kf2 in the above variation. The line it gives is quite convincing: 1.Kc1 Kc7 2.Kd1 Kd7 3.Ke1 Kc7 4.Kf2? and now 4...a3 5.Ke3 Kb6 6.Kd3 Ka5 7.Ke4 Ka4 8.Kd5 a5, forcing self stalemate. The final position is: [D]8/8/5p2/p1pK1P2/k1P2P2/p1P5/P7/8 w - - 0 0 So there is no question their analysis is erroneous. > >I didn't play thru. that variation, but clearly its at least 31ply and white >hasn't even captured a pawn yet! Let me see, finished with white K on f3, so it >needs another 3 moves at the very least to capture c5 so this problem looks like >it is at the VERY least 34ply deep and probably more. > >cheers, >Peter
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