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Subject: Re: Kasparov-Kramnik game 6 49.b4! instead of Kh1 and 54.Qd5! instead Qa8

Author: Uri Blass

Date: 01:57:53 10/19/00

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On October 19, 2000 at 04:09:38, Bill Gletsos wrote:

>Does any program find either of these lines?
>
>
>49.b4! Nxb4 (49...Nd8 50.Rxh7+ Qxh7 51.Qxd5 the difference with the game is
>patent here: Black cannot bring his king closer to the c-pawn with check
>(...Kg6+) and cannot prevent the crushing Qd6: 51...Qc7 52.Qd6+-; Also 49...Ne5
>50.Bxg5+ fxg5 51.Qxf5 Nf3+ 52.gxf3 Rxf5 53.Ra7 is winning, the pawn on b4 makes
>a huge difference here.) 50.Kh2! Nc6 51.g4 winning. A brilliant win, wouldn’t
>you agree?


I did not check the line but I remember that Junior found b4 during the game.
>
>
>also at move 54 instead of Qa8

You mean 56.Qa8 because at move 54 white played Qd5.
>
>54.Qd5! Nc6 55.Bd4! Kg6 (55...Nxd4 56.Qxd4 Qxa5 57.c6 is an easily winning Queen
>endgame.)
 56.Bc3 would have deprived Black of any counterplay. Combining the
>attack on the c6-knight and the f6-pawn with the advance of the kingside pawns
>at the right time would have brought White victory.

The line of Nxd4 that winning a pawn for black is the problem of materialistic
programs.

I am not sure if black is losing and we need to see that there is no perpetual
check for black and that there is no way for black to stop the pawn.

Uri



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