Author: Mogens Larsen
Date: 06:03:24 11/07/00
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On November 07, 2000 at 07:48:19, Uri Blass wrote: >[D]3rr1k1/1bq1b1p1/pp1ppnnp/2p5/2P1P3/1PNBBN1P/P2Q1PP1/R2R2K1 w - - 0 1 >This position is from the ssdf games >The target is to avoid Bxh6. > >The program that are called "bean counters" have no problem to solve it and >never consider Bxh6 as best. I tried a "bean counter". Analysis by LG2000 v2.9a: 1.a3 Ne5 2.Nxe5 dxe5 ² (0.33) Depth: 6 00:00:00 4kN 1.a3 Nd7 2.Rab1 Nde5 ² (0.26) Depth: 6 00:00:00 4kN 1.a3 Nd7 2.Rab1 Nde5 ² (0.26) Depth: 7 00:00:00 23kN 1.a3 Nd7 2.Qc2 Bf6 3.Rac1 ² (0.26) Depth: 7 00:00:00 23kN 1.a3 Nd7 2.Qc2 Bf6 3.Rac1 ² (0.26) Depth: 8 00:00:00 304kN 1.a3 Nd7 2.Rab1 Bf6 3.Rbc1 Rf8 = (0.20) Depth: 8 00:00:01 304kN 1.a3 Nd7 2.Rab1 Bf6 3.Rbc1 Rf8 = (0.20) Depth: 9 00:00:01 1047kN 1.a3 Nd7 2.Rab1 Bf6 3.Rbc1 Nde5 4.Nxe5 Nxe5 = (0.17) Depth: 9 00:00:02 1047kN 1.a3 Nd7 2.Rab1 Bf6 3.Rbc1 Nde5 4.Nxe5 Nxe5 = (0.17) Depth: 10 00:00:06 5132kN 1.a3 Nd7 2.Rab1 Rf8 3.Bc2 Bf6 4.Kh1 Nde5 = (0.15) Depth: 10 00:00:07 5132kN 1.a3 Nd7 2.Rab1 Rf8 3.Bc2 Bf6 4.Kh1 Nde5 = (0.15) Depth: 11 00:00:24 23456kN 1.a3 Nd7 2.Ne1 Bf6 3.f4 Ndf8 4.Rac1 Qf7 = (0.22) Depth: 11 00:00:32 23456kN 1.a3 Nd7 2.Ne1 Bf6 3.f4 Ndf8 4.Rac1 Qf7 = (0.22) Depth: 12 00:00:49 47137kN 1.Bxh6 = (0.23) Depth: 12 00:01:15 47137kN 1.Bxh6 gxh6 2.Qxh6 Nf8 3.e5 Bxf3 4.gxf3 N6h7 5.Kh1 Bg5 6.Rg1 Qf7 7.Rxg5+ Nxg5 8.Qxg5+ Qg7 = (0.22) Depth: 12 00:03:29 47137kN 1.Bxh6 gxh6 2.Qxh6 Nf8 3.e5 Bxf3 4.gxf3 N6h7 5.Kh1 Bg5 6.Rg1 Qf7 7.Rxg5+ Nxg5 8.Qxg5+ Qg7 = (0.22) Depth: 13 00:04:09 291559kN 1.Bxh6 gxh6 2.Qxh6 Nf8 3.e5 Bxf3 4.gxf3 N6h7 5.Kh1 Bg5 6.Rg1 Qf7 7.Rxg5+ Nxg5 8.Qxg5+ Qg7 9.Qh5 ² (0.51) Depth: 13 00:07:42 291559kN 1.Bxh6 gxh6 2.Qxh6 Nf8 3.e5 Bxf3 4.gxf3 N6h7 5.Kh1 Bg5 6.Rg1 Qf7 7.Rxg5+ Nxg5 8.Qxg5+ Qg7 9.Qh5 ² (0.51) Depth: 14 00:07:54 577857kN Best wishes... Mogens
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