Author: Gareth McCaughan
Date: 10:12:11 12/10/00
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On December 10, 2000 at 11:17:58, Uri Blass wrote: > [D]b7/1q2p2k/3p1p1p/1Pr1nP2/6PP/1rN5/2RKBQ2/2R5 b - - 0 1 > > This position is from Fritz-Gambittiger. > > The target is to find Rd5+ that is winning. > > How much time does your program need to find Rd5+? > Is it the simplest way to win the game? Crafty 17.6 on my machine (K6-2/400) chooses ...Qc7 very early and sticks with it for at least 12 minutes. It seems to think it's pretty good. (-0.90 -- i.e., better for Black -- at 12 minutes.) PV at this point is ...Qc7; g5 hxg5; hxg5 fxg5; Qh2+ Kg7; Qh5 Nf7; Qg6+ Kf8; Qe6 d5; Bg4. After playing as far as ...fxg5 and letting it think again for about 2m30, its evaluation and next few moves mostly agree with that. After playing ...Rd5+ and letting it think for about 4 minutes, the evaluation is much the same as after ...Qc7, and the PV begins with Nxd5 Qxd5+ Ke1. After playing those moves, it takes a little while to fail high on ...Rh3, but having resolved the fail-high it still doesn't see the evaluation as being terribly good for Black. Then it fails high again, resolves it at about 3:45, with an evaluation of about -2.06: ...Rh3; Rc3 Rh1+; Bf1 Nd3+; Rxd3 Qxd3; Rd1 Qxb5; h5 Qa5+: Rd2 Qe5+; Qe2 Be4. The first difference between this PV and the one before the second fail-high is resolved is at the move Rd1 (before, it had Qe2).
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