Author: Enrique Irazoqui
Date: 08:23:17 02/25/01
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Weeks ago I posted this problem of Troitzky. Why is it unsolvable? This is the original position: [D]8/3kP3/3br1P1/6P1/7K/8/8/7B w and this the final position after 1.Bc6+! Kxe7 2.Bd5 Rxg6 3.Kh5 Rg7 4.g6 Kf6 5.Bf7 Kf5 6.Kh4 Kf4 7.Kh3! Be7 8.Kg2 Bh4 9.Kf1!= =. Not deep at all. [D]8/5Br1/6P1/8/5k1b/8/8/5K2 b Here Crafty and all the others evaluate it as near +6. Since programs know that KB vs.K is a draw, is it not possible to make abstraction of the trapped piece and the white bishop and pawn that trap it, and then realize it is a draw? Step 1, identify the hopeless trap; step 2, evaluate "as if" black's rook and white's pawn and bishop didn't exist. If such a simple case can't be seen by programs, how can they avoid giving wrong evals when the theme of trapped pieces appear, as in the Sherbakov-Rebel game and several others? It's probably a foolish idea of a programming illiterate, but these cases are quite maddening. Enrique
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