Author: Miguel A. Ballicora
Date: 18:48:27 03/19/01
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On March 19, 2001 at 16:07:18, David Rasmussen wrote: >On March 19, 2001 at 14:22:20, Miguel A. Ballicora wrote: > >>> >>>An int is assured to be at least 32 bits by the ANSI standard. >> >>It is 16, but anyway the problem would be that the standard guarantees "at >>least" a number (16 for int, 32 for long int). That means that in another > >An int with no size modifier is a long int, not a short int, just as it is >signed if there are no signed/unsigned modifiers. So declaring "int a;" gives a >variable which is at least 32 bits. This is in most of the versions now, but it is not guaranteed but the standard (1989) This is a excerpt from Kernighan & Ritchie (2nd edition) 2.2: "short is often 16 bits, long 32 bits, and int either 16 or 32 bits. Each compiler is free to choose appropiate sizes for its own hardware, subject only to the restriction that shorts and ints are at least 16 bits, longs are at least 32 bits, and short is no longer than int, which is no longer than long" When it comes to define INT_MAX and INT_MIN in section B11: "... The values below are acceptable minimum magnitudes; larger values may be used" INT_MAX +32767 INT_MIN -32767 Which are the values that can be represented in 16 bits In fact, some compilers in DOS use 16 bit ints. I used one (TURBO C 3.0) when I started to make my program... So, this could potentially be in conflict with portability of the opening book. But I doubt that any modern compiler uses 16 bit ints, but you never know if you want to port your program to a smaller system... Maybe this is to theoretical unless you care about true portability. I care a bit, for other reasons, to learn the details of the language. On the other hand, I'm lazy :-) Regards, Miguel > >>system >>it could be bigger, corrupting the reading (if it is done by >>sizeof(whatevertype) ) >> >> >>But endianness still is a problem. >> > >Yes. > >>Regards, >>Miguel
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