Author: Dann Corbit
Date: 02:03:23 04/13/01
Go up one level in this thread
On April 13, 2001 at 04:40:05, Gian-Carlo Pascutto wrote:
>Here are his annotations:
>
>On April 13, 2001 at 04:24:58, Dann Corbit wrote:
>>
>>Here is the game.
>>
>>[Event "It"]
>>[Site "Bad Niendorf (Germany)"]
>>[Date "1927.??.??"]
>>[Round "?"]
>>[White "Kmoch, Hans"]
>>[Black "Nimzowitsch, Aron I"]
>>[Result "0-1"]
>>[ECO "B00"]
>>[Opening "KP"]
>>[Variation "Nimzovich defence"]
>>
>>50. Kg3 Rb4
>
>The winning move.
>
>>51. cxb4
>
>Compulsory, or else R-R5; etc
>
>>a4 52. b5+ Kxb5 53. Ba3 c3 54. Rb1 Kc4
I think 54. Rb1 is the question. Alex Szabo provided instead:
54. Re2! Kc4
So the question to be answered is : "Is Rb1 inferior to Re2, and is Re2 saving?"
Here is the current Crafty analysis on that point...
White(1): st 1800
search time set to 1800.00.
White(1): st 7200
search time set to 7200.00.
White(1): epdpfga w230.epd w230.out
PFGA: EPD record: 1
end-game phase
clearing hash tables
time surplus 0.00 time limit 120:00 (120:00)
nss depth time score variation (1)
9 0.16 -1.07 1. Rb1 Kc4 2. Rc1 Kxd4 3. Kf4 Kc4 4.
Bb2 d4 5. Ke4
9-> 0.20 -1.07 1. Rb1 Kc4 2. Rc1 Kxd4 3. Kf4 Kc4 4.
Bb2 d4 5. Ke4
10 0.51 -- 1. Rb1
10 0.98 -2.05 1. Rb1 Kc4 2. Rc1 Kxd4 3. Kf4 Kd3 4.
Rb1 Kd2 5. Bc1+ Kc2 6. Ra1
10-> 1.08 -2.05 1. Rb1 Kc4 2. Rc1 Kxd4 3. Kf4 Kd3 4.
Rb1 Kd2 5. Bc1+ Kc2 6. Ra1
11 2.18 -2.11 1. Rb1 Kc4 2. Kf4 Kxd4 3. f3 Kd3 4.
Rd1+ Kc2 5. Rc1+ Kd2 6. Rb1 Bd7 7.
Rh1 <HT>
11-> 2.48 -2.11 1. Rb1 Kc4 2. Kf4 Kxd4 3. f3 Kd3 4.
Rd1+ Kc2 5. Rc1+ Kd2 6. Rb1 Bd7 7.
Rh1 <HT>
12 5.79 -2.17 1. Rb1 Kc4 2. Kf4 Kxd4 3. Rc1 Kd3 4.
Rd1+ Kc2 5. Rc1+ Kd2 6. Rh1 d4 <HT>
12-> 6.38 -2.17 1. Rb1 Kc4 2. Kf4 Kxd4 3. Rc1 Kd3 4.
Rd1+ Kc2 5. Rc1+ Kd2 6. Rh1 d4 <HT>
13 18.38 -2.49 1. Rb1 Kc4 2. Kf4 Kxd4 3. f3 Kd3 4.
Rd1+ Kc4 5. Rc1 d4 6. Bb2 <HT>
13 20.45 -2.34 1. Re2 Kc4 2. f4 Kxd4 3. f5 exf5 4.
e6 Kd3 5. Re1 Kc4 6. e7 Bd7 7. Kf4
Be8
13-> 20.89 -2.34 1. Re2 Kc4 2. f4 Kxd4 3. f5 exf5 4.
e6 Kd3 5. Re1 Kc4 6. e7 Bd7 7. Kf4
Be8
14 28.71 -- 1. Re2
14 36.30 -2.79 1. Re2 Kc4 2. f4 Kxd4 3. f5 exf5 4.
e6 Kd3 5. Re1 Bxe6 6. Rxe6 b2 7. Re1
f4+ 8. Kxf4 d4
14 47.38 ++ 1. Rb1!!
14-> 59.58 -2.40 1. Rb1
15 2:20 -- 1. Rb1
15 2:53 -2.67 1. Rb1 Kc4 2. Kf4 Kxd4 3. f3 Kc4 4.
Rc1 d4 5. Bb2 Kd3 6. Ba3 Bd7 7. Bb4
b2 <HT>
15-> 3:03 -2.67 1. Rb1 Kc4 2. Kf4 Kxd4 3. f3 Kc4 4.
Rc1 d4 5. Bb2 Kd3 6. Ba3 Bd7 7. Bb4
b2 <HT>
>As White's R and B are immobilised-otherwise P-Kt7; with K-Kt6; is immediately
>decisive-the black K can at leisure feast upon the QP and return to QB5.
>This is the deciding factor.
>
>>55. f4 Kxd4 56. Kf2 Kc4 57.
>>Ke1 d4 58. Ke2 Kd5 59. Kf3 ..
>
>If K-Q3, B-R3 mate
>
>>59. .. Bb7 60. Re1 Kc4+ 61. Kf2 b2 62. f5 exf5 63. e6
>>Bc6 0-1
>
>--
>GCP
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