Author: Bas Hamstra
Date: 08:02:48 04/13/01
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Mine solved it a while ago, but that was mainly due to inaccurate speculative eval. If you give a huge bonus to that connected passer at 6th row it will solve it quickly. Nowadays, with more accurate scoring, Tao does not find it. Bas. On April 13, 2001 at 04:14:13, Bruce Moreland wrote: >This is from a post by Alex Szabo. > >#230 [Rb4 does not win. The main line is, 1... Rb4!? 2. cxb4 a4 > 3. b5+ Kxb5 4. Ba3 c3 5. Re2! Kc4 6. f4 Kxd4 7. f5 exf5 8. e6 Kd3 > 9. e7 Bd7 10. Kf3 d4 11. Rh2 Kc4 12. Rh8 b2 13. Rb8 d3 > 14. Bxb2 cxb2 15. Rxb2 a3 16. Rb7 Be8 17. Ra7 Kb3 18. Ke3 a2 > 19. Kxd3 Kb2 20. Rb7+ Kc1 21. Ra7 =] > > Ra7, Rb6, Rb5, Rd7, Rf7, Rg7, Rh7, Bd7, Kd7, Kb6, Kb5, a4, and Rc7 > are just as good as the book solution Rb4 -- they all hold the game. > >[D]2b5/1r6/2kBp1p1/p2pP1P1/2pP4/1pP3K1/1R3P2/8 b - - 0 1 > >I think this is worth thinking about. After 1. ... Rb4 2. cxb4 a5 3. b5+ Kxb5 >4. Ba3 c3 5. Re2 Kc4 6. f4, we get this: > >[D]2b5/8/4p1p1/3pP1P1/p1kP1P2/Bpp3K1/4R3/8 b - - 0 1 > >6. ... Bd7 is a possibility, but still seems like a draw. > >There is some fascinating stuff going on in the main line. > >WAC attributes this to Nimzovich, but doesn't give a game reference. > >I doubt that the position is solvable by a computer, and if anyone "finds" this, >they've got some lucky eval terms. > >bruce
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