Author: Shep
Date: 10:45:06 04/28/01
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On April 28, 2001 at 10:04:00, Joshua Lee wrote:
>16777216 x 2000 = 33,554,432,000 maybe for each file so 33GB per file again
>times that by between 70 and 200 files if not more does anyone know how many
>files are needed for the 10mans? It could be done just look at the
Where do you get the 2000 from?
From Bob's answer, it follows that some 10-men tables are
16,777,216 x 2 GB = 33,554,432 GB per table (!!).
How many tables are there?
We have 8 positions to be filled (10 - 2 kings) from a set of 5 {Q,R,B,N,P} up
to symmetry.
Maybe someone has the proper formula at hand, wasn't it 8!/(5!*3!) ?
(Shame on me, I should know this sort of thing. :)
That would be 56 possibilities for each distribution.
There are 5 distributions (9-1, 8-2, 7-3, 6-4 and 5-5) up to symmetry, yielding
280 tablebase files.
(Please correct me if this is wrong.)
Assuming not all tables are 33 million gigs, that would still mean we have more
than 6,000 million GB (= 6 million terabytes) for a full 10-man set.
Even if you leave out the nonsensical ones (like KQQQQQQQQK), that's more than
an awful lot!
---
Shep
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