Author: Terry McCracken
Date: 16:30:06 05/04/01
Go up one level in this thread
On May 04, 2001 at 17:47:19, Dann Corbit wrote: >Here is the original problem: >[D]8/k1b5/P4p2/1Pp2p1p/K1P2P1P/8/3B4/8 w - - bm b6+ Be3; id "WAC.100"; > >As you can see, black looks a little zugged. At first glance, the move Kb3 >looks like a pure time-waster. But when you look at the analysis: > >[D]8/k1b5/P4p2/1Pp2p1p/2P2P1P/1K6/3B4/8 b - - acd 23; acn -1724072686; acs 3600; >ce -503; id "WAC.100 after Kb3"; pv Bb8 Bc3 Bxf4 Bxf6 Bd6 Kc3 Bc7 Be7 Be5+ Kd3 >Bd4 Ke2 f4 Kf3 Be3 Bd6 Bd4 Kxf4 Kb6 Be5 Bf2 Bf6 Ka7; > >Maybe it isn't so bad. Opinions? Yes, there are other lines that win. But this line is _not_ the shortest way to "Rome". The fast way, the way I'd play it is 1.b6+!!..Bxb6 2.Kb5! and Black falls rather quickly. 2..Bc7 3.Be3 and Black may as well resign. Terry
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