Author: Mike S.
Date: 02:17:26 06/04/01
Go up one level in this thread
On June 04, 2001 at 04:57:40, Uri Blass wrote: >On June 04, 2001 at 04:35:19, Uri Blass wrote: > >>On June 04, 2001 at 03:36:25, Rudolf Huber wrote: >> >>>A couple of days ago I said (in a discussion about mtd(f)) that my chess >>>program can search the starting position to 30 ply over night when the eval >>>evaluates material only: >>> >>>SOS no eval >>> 1.00 0:00 0.00 1.h3 (2) >>> 2.00 0:00 0.00 1.h3 (45) >>> 3.00 0:00 0.00 1.h3 h6 2.h4 (138) >>> (...) >>(...) >>3)I see that you get depth 1 with only 2 nodes >>(...) >>4)How do you get 45 nodes at depth 2? >>(...) >I guess 2 nodes at depth 1 is because you first use the qsearch to see that >there is no captures and after it generates one node and evaluates it(it is >obvious that all the other will be the same) > >If we use the same principle at depth 2 I get: >1)21 obvious nodes that are root position and positions after one ply. >2)There are no captures after the main line h3 so it is enough to generate one >move to get 1.h3 h6 and get evaluation 0.00 >3)I need to search for a killer move for every other move that is not 1.h3 >so I get 19 lines 1.h4 h6,1.g3 h6,1.g4 h6.... >4)There are captures after some of the lines(I mean d3 h6 and d4 h6 so you need >to search 1.d3 h6 2.Bxh6 Rxh6 >1.d4 h6 Bxh6 Rxh6 so you get more 4 nodes. >Total number of nodes seem to be 21+1+19+4=45 > >I needed a time to see 4 and this is the reason that I did not understand 45 in >a short time. But it was a short time compared to what i.e. I would have needed (if I would even have understood that this was an interesting question looking at that data, from ply 1...3). I want to express that I am quite impressed by this analytical and sharp-witted way of looking at these results Uri has shown. It may look easy after we have read his explanation :o), but it wasn't. The CCC is really a perfect place for computer chess; I can't think of a better example to prove this. Thanks, M.Scheidl
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