Author: Gian-Carlo Pascutto
Date: 10:55:31 06/11/01
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On June 11, 2001 at 13:36:21, Leen Ammeraal wrote: >Although Peter's program can in many ways be better >than mine, I don't see how it can be more accurate, >that is, as long as we regard, for example, >10-5-0 as equivalent to 8-3-4. As you see, I simply >divide the number of draws by 2 and add the result >to either side. It is more accurate simply because it does not have to do that simplification at all! 10 - 5 - 0 -> 89,4% chance that A is better 8 - 3 - 4 -> 92,7% chance >Would that be discutable, you think? Appearently it is, as it gives different results. >If you do, which of these two results would you >prefer? I'm not sure I got the question, but 8-3-4 gives more information than merging it into 10-5. Also, it tells use more about the relative strengths. I am not going to discuss the actual statistics done by the program, because I did not wrote the program nor do I understand the underlying issues enough to be confident discussing it. -- GCP
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