Author: Marcus Kaestner
Date: 03:32:21 07/01/01
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>Is the following situation possible by the rules? >If it is possible that I see it as unfair > >Suppose there are 3 programs that are better than the rest. >suppose 1 and 2 do not play because they have the same operator. >Suppose that the tournament is of 7 rounds. > >1 draws against 3 and win the rest of the games so it gets 6.5 out of 7. >2 draws against 3 and win the rest of the games so it gets 6.5 out of 7. >3 draws agauinst 1 and 2 and wins the rest of the games so it gets 6 out of 7. > >3 scored less points than 1 and 2 so it is not one of the winners. > >If similiar situation happens in regular swiss tournament then 3 is simply >unlucky because there was no agreement before the tournament that 1 is not going >to play with 2. i do not understand what do you mean. what is unfair? in every tournament you can see that the competitors are playing against different opponents. that´s the soul of swiss-tournaments. anyway: if you want to see a disadvantage than those who have more than one program, have the disadvantage. suppose that the person with two programs is high ranked with both programs. so he cannot play against himself, he has to play against lower rated opponents with both programs, which will have a bad effect to his bucholz. so he has to get a half point more than the others if he wants to win. a clearly disadvantage, because also the low ranked programs are nearly equal strong as the high ranked ones. there is not a single program that is remarkable weaker. anyway, we shouldn´t build all constructions possible. it´s only a theoretical discussion. marcus
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