Author: Chris Taylor
Date: 15:20:10 09/19/01
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On September 19, 2001 at 01:10:00, Robin Smith wrote: >Can any programs solve this ending? > >[D] k7/8/4p3/7P/8/3P4/1Bb4P/K7 w - - 0 1 > >Kazantsev, 1950 study > >Solution: 1.Bh8! Fritz 6 - Taylor,C k7/8/4p3/7P/8/3P4/1Bb4P/K7 w - - 0 1 Analysis by Hiarcs 7.32: 1.d4 Kb7 2.Ba3 Kc6 3.Kb2 Bh7 4.Kc3 Kd5 5.Bf8 e5 6.dxe5 Kxe5 7.Bg7+ Ke4 8.h6 Bg8 9.h4 ± (1.17) Depth: 1 00:00:00 ± (1.27) Depth: 17/30 00:05:09 47129kN, tb=11653 1.Bc1 Bxd3 2.Kb2 e5 3.Kc3 Be4 4.Kc4 Kb7 5.Bb2 Kc7 6.Bxe5+ Kd7 7.h6 Ke6 8.Kd4 Bh7 9.Bg7 Bf5 10.Be5 Bh7 ± (1.28) Depth: 17/30 00:06:23 58115kN, tb=17999 ± (1.29) Depth: 18/31 00:09:58 88192kN, tb=35960 1.Bg7 Bxd3 2.Kb2 Bh7 3.Kc3 Kb7 4.Kd4 Kc6 5.Ke5 Kd7 6.Kf6 Ke8 7.Kxe6 Bg8+ 8.Kf6 Bc4 9.h6 Bd3 10.Ke6 Bc4+ 11.Ke5 Bd3 12.Kf6 Bb1 ± (1.33) Depth: 18/31 00:21:34 173604kN, tb=108313 ± (1.34) Depth: 21/31 01:14:23 587417kN, tb=361998 1.Bh8 Bxd3 +- (1.59) Depth: 21/31 03:08:24 1446491kN, tb=745676 +- (1.59) Depth: 21/31 03:08:24 1446491kN, tb=745676 (Taylor, Notts 19.09.2001) Whoops, the oldest! Chris.
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