Author: Uri Blass
Date: 10:21:54 10/07/01
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On October 07, 2001 at 11:51:00, stuart taylor wrote: >On October 07, 2001 at 08:25:28, Uri Blass wrote: > >>On October 07, 2001 at 08:10:15, stuart taylor wrote: >> >>>Also, you can't get anywhere by playing against the SAME program but at >>>different speeds. The slower one will NEVER win, because the one on fast speed >>>knows everything that the one on Palm knows, and at a fraction of the time. >>> But you MIGHT be a bit luckier if you played Palm Tiger vs. Deep Fritz, or >>>Deep Junior. >>>S.Taylor >> >>I disagree here >> >>1)The engines are not the same and tiger14.6 have some knowledge that tiger14 >>does not have >> >>2)Even if you play the same program against itself it is possible that the >>slower hardware will win. >> >>possible explantions: >>1)opening book that lead to disaster for the better hardware >>2)The program on the faster hardware outsearched the program in the slower >>hardware but it did not help. >> >>It is possible that in chess one side wins the queen by a combination only to >>discover later that (s)he is losing the game because of something that both >>sides did not see and the fact that the stonger side can see the loss some plies >>earlier does not help her(him) to save the game because s(he) did not see it in >>the beginning of the combination. >> >>Uri > >I was thinking a long time before posting, that you might reply in this way. But >I expected you would agree that it is mostly true that if a program was playing >the same program (with only a few small improvements) on a (much) faster speed, >the chances of it winning are much greater than if the faster speed program was >a completely different program. You may be right but I am not sure about it. It also depends on the opening book of the program. Let take an extreme case Suppose the opening book of program A always end in checkmate for one of the sides or repetition In this case the results are decided 100% by book when you play A against itself. it does not happen when you play A against B because B always have a move to get A out of book so the engines really play. Uri
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