Author: Dieter Buerssner
Date: 15:11:49 11/10/01
Go up one level in this thread
On November 09, 2001 at 14:03:47, Uri Blass wrote: >I am interested only in the losing material moves in the main line(the analysis >inside the game is only to help programs to get the right conclusion) > >Luba kristol - Uri blass [B80] >[Blass,U] > >1.e4 c5 2.Nf3 d6 3.d4 cxd4 4.Nxd4 Nf6 5.Nc3 a6 6.Be3 e6 7.Qd2 b5 8.f3 Bb7 >9.0-0-0 Nbd7 10.g4 h6 11.Bd3 Ne5 12.Rhe1 b4 13.Nce2 d5 14.Ng3 a novelty? >14...dxe4 15.Bxe4 Nxe4 16.Nxe4 Bxe4 17.fxe4 Bc5 [17...Nxg4 18.Bf4 e5 19.Qg2 h5 >20.h3 exd4 21.hxg4 Rc8 (21...Qf6 22.e5 Qxf4+ 23.Kb1) 22.e5 g5 23.gxh5 b3 24.axb3 >gxf4 25.e6] 18.Qe2 Qb6 19.Kb1 0-0 20.Rd2 a5 21.Red1 Rfd8 22.h3 a4 23.Ka1 b3 >24.a3 Rac8 25.cxb3 [25.c3 Bxa3 26.bxa3 (26.Nf3 Bxb2+ 27.Kxb2 Rxd2+ 28.Nxd2 a3+) >26...Qa5 27.Kb1 (27.Nb5 Rxd2 28.Bxd2 Nc4) 27...Nc4 28.Rd3 (28.Rc1 Nxa3+ 29.Kb2 >Nc4+) 28...Nxa3+ 29.Kb2 Nc4+ 30.Kb1 Rxd4; >25.g5 Bxd4 26.Rxd4 Rxd4 27.Bxd4 Rxc2] 25...axb3 26.Kb1 Qb7 27.Bf4 Nc4 28.Rd3 >Bxa3 29.Rxb3 Qa6 30.Rdd3 Bxb2 0-1 > >I am interested to know if it can be proved be only material evaluation >after learning that Rac8 wins more than 1 pawn. Analysing from back to front, in your main line, after 25...axb3 I get with material only evaluation (German piece letters: S->N, L->B, T->R, D->Q): 6.34 0:00 -1.60 26.Df2 Sc4 27.e5 Sxd2 28.Txd2 Ta8 29.Kb1 (114.114) 183.1 7.01 0:01 -1.60 26.Df2 Sc4 27.e5 Sxd2 28.Txd2 Ta8 29.Kb1 Kh7 (206.928) 202.4 7.34 0:01 -1.60 26.Df2 Sc4 27.e5 Sxd2 28.Txd2 Ta8 29.Kb1 Kh7 (347.345) 210.1 8.01 0:02 -2.00-- 26.Df2 Sc4 27.e5 Sxd2 28.Txd2 Lxd4 29.Txd4 Txd4 30.Lxh6 (549.219) 212.7 8.01 0:04 -2.68 26.Df2 Sc4 27.Tf1 f5 28.Tc1 Sxd2 29.Dxd2 e5 30.Txc5 Txc5 (871.896) 209.0 8.03 0:04 -2.67++ 26.Sxb3 Txd2 27.Lxc5 Dxb3 28.Dxd2 Txc5 29.Th1 Da4 30.Dd8+ De8 31.Dxe8+ Kh7 (1.051.210) 214.3 8.03 0:05 -2.60 26.Sxb3 Txd2 27.Lxc5 Dxb3 28.Dxd2 Txc5 29.Th1 Da4 30.Dd8+ Kh7 31.Te1 (1.125.349) 215.1 8.25 0:08 -1.60++ 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (1.795.590) 223.0 8.25 0:08 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (1.795.591) 222.9 8.34 0:08 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (1.795.600) 222.9 9.01 0:08 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (1.795.601) 222.9 9.34 0:14 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (3.429.304) 231.1 10.01 0:14 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (3.429.305) 231.0 10.34 0:26 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (6.199.044) 235.1 11.01 0:26 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (6.199.045) 235.1 11.34 0:57 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (13.757.574) 239.9 12.01 0:57 -1.60 26.Df1 Ta8 27.Kb1 Db7 28.Sxb3 (13.757.575) 239.9 Pawn value is 0.8, so this is 2 pawns. It is no proof, because I cannot see how to prove that with longer analysis white cannot win back material. I gave up to go further back, because I could not find a material advantage of 2 pawns fast for your line 25. c3 Bxa3 26. Nf3 Bxb2+ 27. Kxb2 Rxd2+ 28.Nxd2 a3+. What I found is N+3Ps (for black) vs. R here only. But I also did not try for longer time. Regards, Dieter
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