Author: José Carlos
Date: 08:16:20 12/27/01
Go up one level in this thread
On December 27, 2001 at 09:11:23, Michel Langeveld wrote:
>On December 27, 2001 at 09:02:00, José Carlos wrote:
>
>>
>> When things like these happen, I don't know whether it is the compiler that
>>doesn't work or I'm losing my mind. Yesterday I added this piece of code:
>>
>>for (i=0;i<PosActual->NumPeonesB;i++)
>>{
>> cCol=Columna(g_iPL_PB[i]);
>> cFil=Fila(g_iPL_PB[i]);
>> if (cFil>Retrasado(uPeonesB[cCol]))
>>uPeonesB[cCol]=(ParteAvanzada(uPeonesB[cCol]))|(unsigned int)(cFil);
>> if (cFil<Avanzado(uPeonesB[cCol]))
>>uPeonesB[cCol]=(cFil<<16)|ParteRetrasada(uPeonesB[cCol]);
>>}
>>for (i=0;i<PosActual->NumPeonesN;i++);
>
>You have an ; after the for. This probably not what you want.
A typo, sorry. It's not in my code. I removed the comments before posting the
code here and placed that ; for error.
>>{
>> cCol=Columna(g_iPL_PN[i]);
>> cFil=Fila(g_iPL_PN[i]);
>> if (cFil<Retrasado(uPeonesN[cCol]))
>>uPeonesN[cCol]=(ParteAvanzada(uPeonesN[cCol]))|(unsigned int)(cFil);
>> if (cFil>Avanzado(uPeonesN[cCol]))
>>uPeonesN[cCol]=(cFil<<16)|ParteRetrasada(uPeonesN[cCol]);
>> i++;
>>}
>
>And about the counter
>for (int i=0; i<7; i++)
>{
> cout << i << endl;
>}
>
>cout << i << endl;
>
>means that the counter printed is 7 at last.
>In my opinion it's better not to rely i = 7 and make your code robust.
I don't understand this. I want to loop through the pawn list. I have 8 pawns,
so I loop between 0 and 7 (i<8). What do you mean? Better to write i<=7 instead?
José C.
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