Author: Thomas Mayer
Date: 07:21:08 01/03/02
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Hi Gian-Carlo, >> well, it needs 36.47 seconds to discover it - many engines find the solution >> one or more ply's earlier... that is not a good sign... :) >a) what matters is the time to find it, not ply depth or node count Well, my time is not very good when you look on other results - if Quark would be capable to find it one ply earlier it would be much faster... >b) the variations that are displayed are smaller than the nominal ply depth, so >you are probably counting plies in a different way than others do. No no, I cut them - because I can't see in this input window how many space I have left... and those tables with variations over two lines do not look very nice - for the future I should program a little nicer output for Quarks log... :) But just before CCT4 that is definitely not the most important point on my to do list... :) Greets, Thomas
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