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Subject: Re: Nice riddle

Author: Eric Campos

Date: 21:53:25 01/08/02

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Such a simple problem, yet so far from being intuitive.  But when you look at
the problem backwards, it becomes intuitive again.  So ask your friend to look
at the problem backwards:

Let her find the prize by eliminating the incorrect doors.

Your friend already agrees that she can pick an "empty" door 2/3 of the time.
In these 2/3 cases, the quizmaster will eliminate the other "empty" door, and
only the prized door will remain.  We should all win this game 2/3 of the time!

Once she agrees she can win this game 2/3 of the time, remind her that she did
so by first selecting one door, then letting the quizmaster help, then
eliminating (swapping) her first choice!

Swap:     correct 2/3 of the time.
No Swap:  correct 1/3 of the time.

Eric

On January 07, 2002 at 20:24:01, Hans van der Zijden wrote:

>You are in a quiz and you have to choose one of three doors. Behind one of the
>doors is a nice price (lets say an AMD 2000+ with all the chessprograms you
>want, to make it a computerchess topic). The other doors are empty. When you
>tell the quizmaster your choice he opens one of the other doors which is empty.
>Now he is giving you the option to change your mind. Should you stick with your
>first choice, should you change or doesn't it make a difference?
>
>If you don't know this riddle, try to find the solution before reading on.
>
>I told a friend this riddle and she is still convinced that it doesn't matter if
>you change or not. She agrees that you have 1/3 chance getting it right the
>first guess, but after one (empty) door is opened she keeps saying there are 2
>doors left, so now you have 1/2 chance if you stick to your choice. I try to
>explain it to her in all the ways I could think of, but she is as stubborn as 3
>mules. I also played this situation 30 times with and 30 times without changing.
>She thinks I was lucky and the random die showed too many times the number 1.
>Anyone an idea how to explain this to her.
>
>
>Solution:
>
>Suppose you choose door number 1 and you do not change. There are three
>possibilities:
> a. The price is behind door number 1 so you are right
> b. The price is behind door number 2 so you are wrong
> c. The price is behind door number 3 so you are wrong
>So the chance is 1/3.
>
>Now a door is opened.
>In situation a the quizmaster will open door 2 or 3, you don't change, you win.
>In situation b the quizmaster will open door 3, you don't change, you lose.
>In situation c the quizmaster will open door 2, you don't change, you lose.
>So still your chance is 1/3
>
>Now you are going to change. Again lets say you choose 1 and again there are
>three possibilities:
> a. Price is behind door 1, quizmaster opens door 2 or 3, you change, you lose.
> b. Price is behind door 2, quizmaster opens door 3, you change, you win.
> c. Price is behind door 3, quizmaster opens door 2, you change, you win.
>So if you change you have 2/3 chance of getting the big price.
>
>Greetings, Hans.



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