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Subject: Re: perfect ordering

Author: Robert Hyatt

Date: 12:12:19 01/09/02

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On January 09, 2002 at 12:50:12, David Hanley wrote:

>I have seen it claimed somewhere that with perfect move ordering, an eight ply
>search would only consume a thousand nodes or so, even only alphabeta ( no
>hashing or forward pruning ).
>
>Is this so?
>
>dave


Not necessarily.  The _exact_ formula is

N=W^floor(D/2)+W^ceil(D/2)

W is the branching factor, or number of legal moves at a ply
(yes, it is an average value for chess, and the typical value
is 38).

D is the search depth in plies

floor means to "round down"

ceil means to "round up"

If D is even, then a simpler representation is

N = 2 * W^(D/2)

N is the total nodes searched...




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