Author: James T. Walker
Date: 14:59:24 01/22/02
Go up one level in this thread
On January 22, 2002 at 14:40:46, Robert Hyatt wrote: >On January 22, 2002 at 12:38:17, James T. Walker wrote: > >>On January 22, 2002 at 12:26:30, Sune Fischer wrote: >> >>>On January 22, 2002 at 11:58:39, Robert Hyatt wrote: >>> >>>>On January 22, 2002 at 10:30:51, James T. Walker wrote: >>>> >>>>>On January 22, 2002 at 10:27:30, Robert Hyatt wrote: >>>>> >>>>>>On January 22, 2002 at 04:57:05, Sune Fischer wrote: >>>>>> >>>>>>>On January 22, 2002 at 00:35:48, Robert Hyatt wrote: >>>>>>> >>>>>>>>On January 21, 2002 at 18:50:22, David Rasmussen wrote: >>>>>>>> >>>>>>>>>How much space does all the 5-man tables take? >>>>>>>>>When people write 3-4-5 man tablebases, do they mean _all_ of them, or just all >>>>>>>>>3 and 4 man, and then some 5 man. If yes, which ones? >>>>>>>>> >>>>>>>>>/David >>>>>>>> >>>>>>>> >>>>>>>>All of the 3/4/5 piece files require about 7.5 gigs of space... >>>>>>> >>>>>>>I think you mean 7.05 GB. >>>>>>>:) >>>>>>> >>>>>>>-S. >>>>>> >>>>>> >>>>>>No... I mean _exactly_ 7411980 bytes. >>>>>> >>>>>>:) >>>>> >>>>>If you have only 7 Megabytes you are missing a lot >>>> >>>> >>>>Sorry... that was in terms of 1024 byte blocks. I have 'em all, believe >>>>me. :) >>>> >>>>that is 7,589,867,520 bytes if my math works out right. :) >>> >>> >>>and 7,589,867,520 bytes/1024^3 = 7.068 gigabytes :) >> >>Not on my calculator! > > >Depends on your definition of "gigabyte". If you use the rounded value of >1,000,000,000 bytes, you get one answer. If you use the right power of 2, >(2^30) you get a different answer. :) Well I was responding to the math problem he posted. "7,589,867,520 bytes/1024^3 = 7.068 gigabytes" When I divide 7,589,867,520 by 1024^3 I get 7411.98 which is what you had. Now If 1 gigabyte is 1024 Megabytes and 1 Megabyte is 1024 Kilobytes and 1 Kiltbyte is 1024 bytes then you have to divide by 1024 several times and then you get the 7.0686 Gigabytes.
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