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Subject: Re: Testing Silicon: Finding the Bobby moves...

Author: gervais

Date: 12:10:09 01/27/02

Go up one level in this thread


On January 27, 2002 at 14:16:27, Roy Eassa wrote:

>On January 27, 2002 at 02:38:11, gervais wrote:
>
>>Hi,
>>   I am an amateur chess player looking for a possible upgrade from my old
>>Pentium 166. I am using Fritz 6 as my main chess program.
>>While looking at some classical games recently, I saw one from Fischer with a
>>brilliant combination.(IMHO). I decided I would upgrade my system if I could
>>be shown that current hardware/software is able to find this combination  within
>>a reasonable amount of time.
>>
>>[Event "US Championship"]
>>[Site "NY USA"]
>>[Date "1963.12.18"]
>>[Round "3"]
>>[White "Robert Byrne"]
>>[Black "Robert J. Fischer"]
>>[Result "0-1"]
>>
>>1.d4 Nf6 2.c4 g6 3.g3 c6 4.Bg2 d5 5.cxd5 cxd5 6.Nc3 Bg7 7.e3 O-O 8.Nge2 Nc6
>>9.O-O b6 10.b3 Ba6 11.Ba3 Re8 12.Qd2 e5 13.dxe5 Nxe5 14.Rfd1 Nd3 15.Qc2 Nxf2
>>16.Kxf2 Ng4+ 17.Kg1 Nxe3 18.Qd2 Nxg2 19.Kxg2 d4 20.Nxd4 Bb7 21.Kf1 Qd7! (0-1)
>>
>>The FEN is:  r2qr1k1/p4pbp/bp3np1/3p4/8/BPNnP1P1/P1Q1NPBP/R2R2K1 b - - 2 15
>>
>>Think the FEN is ok.(its my first FEN!)
>>
>>So my question is: Can your computer find the follow-up to 15....Nxf2 right
>>till 21....Qd7? How long does it take to see the complete sequence of moves
>>that cause resignation? (15...Nxf2 is easy, but does it see everything
>>up to 21...Qd7 right from the start?)
>>Programs, Fritzmarks,processors, NPS, Ram,Mhz... Spare me no details :)
>>
>>Thanks and I hope to be shopping soon...
>
>
>More reasonable for today's computers might be the position after 18.Qd2 -- how
>long to choose 18...Nxg2, and how long before that move scores over +1 for Black
>(0:31 and 2:16, respectively on my test):
>
>[d] r2qr1k1/p4pbp/bp4p1/3p4/8/BPN1n1P1/P2QN1BP/R2R2K1 b - - 0 1
>
>Analysis by Fritz 7 (Athlon 1.2 GHz):
>
>18...Rc8 19.Nd4 Bxd4 20.Qxd4 Nc2 21.Qd2 Nxa3 22.Nxd5
>  =  (0.09)   Depth: 7/22   00:00:00  493kN
>18...Rc8 19.Nd4 Bxd4 20.Qxd4 Nc2 21.Qa4 Nxa1 22.Rxa1 Rxc3 23.Qxa6
>  =  (0.03)   Depth: 8/21   00:00:00  605kN
>18...Rc8 19.Nd4 Bxd4 20.Qxd4 Nc2 21.Qa4 Rxc3 22.Rxd5 Qc8 23.Rc1
>  =  (0.15)   Depth: 9/24   00:00:02  1625kN
>18...Bxe2!
>  =  (0.12)   Depth: 9/24   00:00:02  1696kN
>18...Bxe2 19.Nxe2 Bxa1 20.Rxa1 Nxg2 21.Kxg2 Qf6 22.Nd4 Qe5 23.Rc1 Qe4+ 24.Kg1
>Rac8
>  =  (0.21)   Depth: 10/28   00:00:09  5838kN
>18...Rc8!
>  =  (0.18)   Depth: 10/28   00:00:10  6116kN
>18...Rc8 19.Nd4 Bxd4 20.Qxd4 Nc2 21.Qa4 Rxc3 22.Bb2 Rce3 23.Qxa6 Nxa1 24.Rxa1
>  =  (0.21)   Depth: 11/29   00:00:26  16251kN
>18...Nxg2!
>  =  (0.18)   Depth: 11/31   00:00:31  19735kN
>18...Nxg2 19.Kxg2 d4 20.Nxd4 Bb7+ 21.Kf1 Qd7 22.Qf2 Bxd4 23.Rxd4 Qc6 24.Bb2 Qh1+
>25.Qg1 Qf3+
>  =  (0.00)   Depth: 12/33   00:01:01  38576kN
>18...Nxg2!
>  =  (-0.22)   Depth: 13/33   00:02:00  76850kN
>18...Nxg2!
>  ³  (-0.50)   Depth: 13/33   00:02:05  80471kN
>18...Nxg2!
>  µ  (-1.07)   Depth: 13/33   00:02:16  87417kN
>18...Nxg2 19.Kxg2 d4 20.Nxd4 Bb7+ 21.Kf2 Qd7 22.Nce2 Rad8 23.Qc2 Qh3 24.Nf3 Bxf3
>25.Kxf3 Bxa1
>  µ  (-1.25)   Depth: 13/37   00:02:44  103919kN
>18...Nxg2 19.Kxg2 d4 20.Nxd4 Bb7+ 21.Kf2 Qd7 22.Nf3 Qxd2+ 23.Nxd2 Bxc3 24.Rac1
>Bd4+ 25.Kf1 Bc8
>  -+  (-1.50)   Depth: 14/37   00:04:22  164445kN
>18...Nxg2 19.Kxg2 d4 20.Nxd4 Bb7+ 21.Kf2 Qd7 22.Nf3 Qxd2+ 23.Nxd2 Bxc3 24.Rac1
>Bd4+ 25.Kf1 Bc8
>  -+  (-1.47)   Depth: 15/41   00:08:04  303919kN

Hi and thanks to Kurt and Roy,

        I guess its time for me to reduce my expectations.(Although Roy's
results on Athlon 1.2Ghz/Fritz 7 are very interesting). This combination is long
and difficult and perhaps the 21.Kf2 sub-variation is creating the difficulties.
Citing Fischer in "My Sixty Memorable Games": 21.Kf2 Qd7!
22.Rac1 Qh3 23.Nf3 Bh6 24.Qd3 Be3+ 25.Qxe3 Rxe3 26.Kxe3 Re8+ 27.Kf2 Qf5! finis!
(Roy, Fischer seems to prefer 22.Rac1 to 22.Nf3).

So, for a more realistic question(than my first one): Can recent
computers/software find the line starting from 22...Qh3 up to 27...Qf5! in this
sub-variation in a reasonable time?

The FEN is:  r3r1k1/pb1q1pbp/1p4p1/8/3N4/BPN3P1/P2Q1K1P/2RR4 b - - 0 22

Thanks again











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