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Subject: Re: More correct analysis here...

Author: Uri Blass

Date: 23:44:40 01/31/02

Go up one level in this thread


On February 01, 2002 at 00:28:08, Robert Hyatt wrote:

>On January 31, 2002 at 14:04:13, Andrew Dados wrote:
>
>>
>>
>>From their own publication, 'Deep Blue', June 2001
>>Example of search depths over one position
>>r1r1q1k1/6p1/3b1p1p/1p1PpP2/1Pp5/2P4P/R1B2QP1/R5K1 w
>>from DB-Kasparow game 2 from 1997, before move 37
>>
>>When chips were set to minimum fullwith 4 plys:
>>
>>A.Iteration
>>B.Minimum software depth
>>C.Maximum software depth
>>D.Maximum Estimated combined depth
>>
>>A  B  C    D
>>----------------
>>6  2  5  11-21
>>7  3  6  12-22
>>8  4  11 17-27
>>9  5  15 21-31
>>10 6  17 23-33
>>11 7  20 26-36
>>12 8  23 29-39
>>
>>So iteration is clearly the sum of minimum software depth (B) and hardware depth
>>(4 plys here).
>>
>>-Andrew-
>
>
>
>OK... but what does this have to do with the current discussion?  DB doesn't
>report "an iteration number".  It reports things like 10(6) and directly
>according to Hsu (from the email I posted) 10 is the software depth, and (6)
>is the hardware depth.  They are _added_ to get the total depth...

I also do not understand the fixed depth of the hardware of 4 plies but it is
clear thank to previous post of andrew Dados that 18 plies is impossible.

He gave discussion from rgcc when one(david fotland if I remember correctly)
said in march 1997 that deeper blue team decided not to search 14 plies brute
force but search only 11-12 plies because they wanted to do more extensions

Nobody corrected him at that time and I see no publication when hsu says that
12(6) means 18 plies brute force.

Here is the logfile from the game and I do not see hint for a fixed depth of 4
plies for hardware from it


-->  36.   axb5 <-- 4/40:28
---------------------------------------
hash guess Pa6b5p,Guessing axb5
 8(4) #[Qb6](30)[Qb6](30) 30^ T=1
qf2b6 Ra8a2r ra1a2R Bd6c7 qb6e6 Kg8h8 bc2e4 Rc8b8 ra2a6 Qe8d8 pd5d6 Bc7b6
 8(6) #[Qb6](53)#################################### 53  T=4
qf2b6 Ra8a2r ra1a2R Bd6c7 qb6e6 Kg8h8 bc2e4 Rc8b8 ra2a6 Qe8d8 pd5d6 Bc7b6
 9(6) #[Qb6](53)#################################### 53  T=9
qf2b6 Ra8a2r ra1a2R Bd6c7 qb6e6 Kg8h8 bc2e4 Rc8a8 kg1h2 Ra8b8 pg2g3 Qe8f8
10(6) #[Qb6](55)#################################### 55  T=33
qf2b6 Ra8a2r ra1a2R Bd6c7 qb6e6 Kg8h8 bc2e4 Qe8f8 kg1h1 Bc7d6 ra2a6 Rc8d8 ra6a7
11(6)<ch> 'ab'
 #[Qb6](32)########[Be4](37)############################ 37  T=182
bc2e4 Rc8b8 pg2g3 Qe8d8 ra2a6 Ra8a6r ra1a6R Bd6c7 ra6f6P
12(6)[TIMEOUT] 37  T=199
bc2e4 Rc8b8 pg2g3 Qe8d8 kg1g2 Ra8a2r ra1a2R Bd6c7 qf2a7 Bc7b6 qa7a6 Qd8d7
---------------------------------------
-->  37.   Be4 <-- 3/37:56


Uri



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