Author: pavel
Date: 20:22:32 02/06/02
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On February 06, 2002 at 22:47:08, Robert Hyatt wrote: >On February 06, 2002 at 20:05:18, Eran wrote: > >>On February 06, 2002 at 18:12:11, Dann Corbit wrote: >> >>>[D]4k3/Q3p1Q1/1Q5B/Q1QN1NQ1/4QQ2/B2Q4/8/2R1KR2 w - - acd 4; acn 29; acs 0; bm >>>Nc7# Nd6# Nf6# Q5g6# Q7g6# Qaa4# Qab5# Qaxe7# Qbb5# Qbb8# Qbc6# Qbg6# Qc8# Qcb5# >>>Qcc6# Qcxe7# Qd8# Qdb5# Qea4# Qexe7# Qf8# Qfb8# Qg5xe7# Qg7xe7# Qg8# Qh5#; ce >>>32766; dm 1; pv Nd6#; >>> >>>I have found that some programs crash, and others think for minutes on this mate >>>in 1. >> >>Your position is not realistic, because nine White Queen pieces are on the >>board. In fact, every game each side cannot have more than eight pawns. If a >>player promotes all his/her eight pawns, there will be no more than eight Queen >>pieces on his/her side. Therefore, your position is baloney! It never happened. >> >>Eran > > >What about the _original_ queen? 8 pawn promotions + one original queen >= nine queens? This is only possible if I am playing (with black) against kramnik. I don't see how else this could be possible. pavs
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