Computer Chess Club Archives


Search

Terms

Messages

Subject: Nalimov Mate in X question

Author: Edward Seid

Date: 20:50:48 02/06/02


Question regarding the announcement of Mate in X when using tablebases.

How is X determined?  My guess is that it is the summation of the number of
moves to conversion to the next lower tablebase.

If true, then I have a scenario.

Assume a 4-piece ending.  Using tablebases, White announces Mate in 20.  Using
the above definition of Mate in X, White sees Mate in 20 because the nearest
conversion to a 3-piece tablebase is 10 moves, from which there is forced mate
in 10.

Now let's assume that White chooses NOT to play for the nearest conversion, but
instead plays for a 12-move conversion to a 3-piece ending in which mate is
forced in 6.  In the second case, even though White chooses a longer path to
conversion, it actully results in a shorter Mate in 18.

Is this possible?



This page took 0 seconds to execute

Last modified: Thu, 15 Apr 21 08:11:13 -0700

Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.