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Subject: Re: Agree it's too hard; how long to find the simpler move 4?

Author: Roy Eassa

Date: 13:38:46 02/08/02

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Agreeing that Ali's puzzle is too hard for computers to find in a reasonable
length of time, how long does it take your favorite program to find 4.Bd3+ and
see that it is winning?

Here's Fritz 7b on a 1.2 GHz Athlon:

[d] r1bq1r2/p2np2k/3p4/3pP3/2pP3N/4Q3/PP4P1/2KR1B2 w - - 0 1

4.Bxc4 Qc7 5.Qd3+ Kh8 6.Ng6+ Kg7 7.Nxf8 Qxc4+ 8.Qxc4 dxc4 9.Ne6+ Kg6
  -+  (-1.81)   Depth: 7/24   00:00:00  133kN
4.Bxc4 Qc7 5.Qd3+ Kh8 6.Ng6+ Kg7 7.Nxf8 Nxf8 8.exd6 Qxc4+ 9.Qxc4
  -+  (-2.03)   Depth: 8/26   00:00:00  245kN
4.Qg5!
  -+  (-2.00)   Depth: 8/26   00:00:00  310kN
4.Qg5!
  -+  (-1.84)   Depth: 8/26   00:00:00  324kN
4.Qg5!
  -+  (-1.53)   Depth: 8/26   00:00:00  354kN
4.Qg5!
  µ  (-0.90)   Depth: 8/26   00:00:00  421kN
4.Qg5!
  ³  (-0.62)   Depth: 9/28   00:00:01  750kN
4.Qg5!
  ³  (-0.34)   Depth: 9/28   00:00:01  959kN
4.Qg5 Nf6 5.Nf3 Kh8 6.exf6 exf6 7.Qh6+ Kg8 8.Qg6+ Kh8 9.Qh6+ Kg8 10.Qg6+ Kh8
11.Qh6+
  =  (0.00)   Depth: 9/31   00:00:03  1812kN
4.Qg5 e6 5.Qg6+ Kh8 6.Qh6+ Kg8 7.Qg6+ Kh8 8.Qh6+ Kg8 9.Qg6+ Kh8 10.Qh6+ Kg8
11.Qg6+
  =  (0.00)   Depth: 10/32   00:00:10  5650kN
4.Qg5 e6 5.Qg6+ Kh8 6.Qh6+ Kg8 7.Qg6+ Kh8 8.Qh6+ Kg8 9.Qg6+ Kh8 10.Qh6+ Kg8
11.Qg6+
  =  (0.00)   Depth: 11/35   00:00:25  12167kN
4.Qg5 e6 5.Qg6+ Kh8 6.Qh6+ Kg8 7.Qg6+ Kh8 8.Qh6+ Kg8 9.Qg6+ Kh8 10.Qh6+ Kg8
11.Qg6+
  =  (0.00)   Depth: 12/36   00:01:01  28025kN
4.Qg5 e6 5.Qg6+ Kh8 6.Qh6+ Kg8 7.Qg6+ Kh8 8.Qh6+ Kg8 9.Qg6+ Kh8 10.Qh6+ Kg8
11.Qg6+
  =  (0.00)   Depth: 13/37   00:02:38  80422kN
4.Bd3+!
  =  (-0.03)   Depth: 13/41   00:03:43  117419kN
4.Bd3+!
  =  (0.13)   Depth: 13/41   00:03:58  125961kN
4.Bd3+!
  ²  (0.44)   Depth: 13/41   00:04:15  135503kN
4.Bd3+!
  ±  (0.72)   Depth: 14/40   00:06:49  226362kN
4.Bd3+!
  ±  (1.00)   Depth: 14/40   00:07:29  249570kN
4.Bd3+ cxd3 5.Qxd3+ Kh8 6.Rh1 Rf1+ 7.Qxf1 Kg8 8.Qf3 Nf8 9.Qg3+ Kf7 10.Rf1+ Ke8
11.Qg8
  +-  (1.44)   Depth: 14/41   00:09:01  301594kN



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