Author: Dann Corbit
Date: 15:27:14 02/22/02
Go up one level in this thread
On February 22, 2002 at 17:18:04, Angrim wrote: >On February 22, 2002 at 14:21:01, Paul Doire wrote: > >>When chess is "figured out" what ELO will that equate to? >> >>Paul > >This depends on which rating pool you are measuring it in. >Also depends on if the result of the perfect game is a draw or >a win for white. In either case, you can not rationally expect >that the perfect player will always win, especially if it is >playing a series vs an opponent who can learn. > >Given that, here is one implausable scenario in which the >answer can actually be calculated. >Assume that this perfect player is playing on ICC, and that it >always wins, and that the top-rated players are actually >willing to play it, and that the top rated players don't have their >ratings change any from what they are today at 3pm.. > >then its rating would be: >standard: 2839+720=3559 >blitz: 3460+720=4180 >bullet: 3167+720=3887 > >This is based on the following from an ICC help file: >This formula has the property that if both players are established then the >sum of the rating changes is zero. It turns out that if the rating difference >is more than 719 points, then if the strong player wins, there is no change in >either rating. >So given all of the unlikely assumptions that I listed, the >perfect player would be rated 719 points higher than the second best player. What if there are a thousand players, each one dominating over the one beneath? If the bottom player is 0, then the top 719,000? What if the lowest rated player is at 4000? 40,000, 4e100?
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