Author: Dieter Buerssner
Date: 16:27:20 03/10/02
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On March 10, 2002 at 18:53:59, Guido wrote: >I follow the same logic, but the value you obtain 462*62=28644 doesn't take into >account that positions of the Queen/Rook are not 62 when the two Kings are on >the diagonal a1h8. There are 21 of such positions for the Kings, and in these >cases the Queen/Rook has only 34 square. Therefore: > >28644 - 21*(62-34) = 28056 > >Using the same reduction it is possible that you obtain the same number as me >also for wtm. Thanks for pointing this out. I agree with your reasoning, and stand corrected. For my usuage, I believe this additional symmetry is not worthwhile, so I did not code it (and actually, I did not even think of it ...) Ciao, Dieter
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