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Subject: EGTB question to Martin Fierz

Author: Alvaro Jose Povoa Cardoso

Date: 00:05:30 04/04/02


Hi Martin,
I red the Chinook team article on EGTB ("Solving Large Retrograde Analysis
Problems").
In my mind I was picturing an EGTB entry as a byte with 2 bits for position
classification (win, loss, draw, unkown) and 6 bits for a distance to win/loss
metric.
But in the article they mention the use of only 2 bits, leaving out the distance
to win/loss information.
My question is: using only 2 bits how can the engine make progress?
How can he find the shortest win or the longest loss without those 6 bits of
information?

Best regards,
Alvaro Cardoso



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