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Subject: EGTB algoritmic question

Author: Alvaro Jose Povoa Cardoso

Date: 11:00:44 07/10/02

As far as I understand EGTB generation, it works by finding all wins/losses in
1, then all wins/losses in 2, then all wins/losses in 3, and so on.
My question arises from a bug(s) in my generator and the question is:
Is there any possibility of an EGTB generator _after_ finding all wins/losses in
4 for example, later it finds a win/loss in 3 or in 2?
If we find a position's child that wins in 4 then, in the next pass, we can't
possibly find another child that wins in 3 right?

Best regards,
Alvaro Cardoso

• Re: EGTB algoritmic question GuyHaworth 11:17:04 07/10/02
  • Re: EGTB algoritmic question Daniel Clausen 13:23:54 07/10/02
    • ... a 'deferring' DTM EGT algorithm GuyHaworth 00:45:55 07/13/02
      • Re: ... a 'deferring' DTM EGT algorithm Vincent Diepeveen 07:35:32 07/13/02
    • Re: EGTB algoritmic question Simon Finn 05:45:09 07/11/02

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