Author: Richard Bean
Date: 09:32:39 07/13/02
Go up one level in this thread
On July 13, 2002 at 10:30:28, Robert Hyatt wrote: >>6 119060324 9417681 >>The reason I differ from Steven Edwards for the number >>of unique nodes at ply 6 is that after the moves >>1. f4 e6/e5 2. Kf2 Qf6 3. f5 g5, no ep capture is possible, >>so I get 2 less unique nodes than him. >> > >This is _supposed_ to be _legal_ moves only. I don't therefore see >why Steven would be counting an EP move that can't be made... I'm counting unique nodes at ply 6 - you can look at http://www.it.ro/ccc_search/ccc.php?art_id=147499 and check that Andreas Stabel got 2 less nodes when he counted positions as unique only if ep captures were legal. What I'm really saying is: consider the positions after the moves 1. f4 e6 2. Kf2 Qf6 3. f5 g5 - a 1. f4 g5 2. Kf2 e6 3. f5 Qf6 - b 1. f4 e5 2. Kf2 Qf6 3. f5 g5 - c 1. f4 g5 2. Kf2 e5 3. f5 Qf6 - d I think Steven Edwards has counted this as four unique positions whereas I only count it as two, because 4. fxg6 is illegal in a and c and impossible in b and d.
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