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Subject: enable/disable code

Author: Steffen Jakob

Date: 01:01:23 07/22/02

Go up one level in this thread


On July 21, 2002 at 21:36:53, Miguel A. Ballicora wrote:
>
>>1)How do I add a code with compiler switch?
>>
>you define a variable like this:
>
>#define HASH_PRUNE
>
>and then you do
>
>
>#if defined(HASH_PRUNE)
>    code_1();
>#else
>    code_2();
>#endif
>
>code_1() is compiled and NOT code_2(). Also valid options are
>
>#ifdef HASH_PRUNE
>    code_1();
>#else
>    code_2();
>#endif
>
>or
>
>#if defined(HASH_PRUNE)
>     optional_code();
>#endif

The problem with that approach is that you actually have two different programs.
If you work for a long time with a switch enabled its likely that your code wont
compile if you disable the switch. A better solution in many cases is to use a
const boolean expression. You favourite compiler will skip the code if the
expression is false.

Example:

const bool HASH_PRUNE = true;

if (HASH_PRUNE) {
    code_1();
} else {
    code_2();
}

This doesnt work of course if you want to modify structs depending on such a
const.

Greetings,
Steffen.



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