Author: Tina Long
Date: 20:39:43 07/28/02
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On July 28, 2002 at 23:03:47, Privacy Privacy wrote: >Hi... > >I'm an intermediate player, yet I have some questions I cannot find answers to >as to the scoring and listing of players on crosstables etc. For example, in >this tournament: > >ch-SVK Kaskady SVK 2002 > > 1 2 3 4 5 6 7 8 9 0 1 2 >1 Sutovsky,E 2660 +79 * ½ ½ ½ ½ 1 1 ½ 1 1 1 1 8.5/11 >2 Landa,K 2623 +76 ½ * 0 ½ ½ 1 ½ 1 1 1 1 1 8.0/11 >3 Romanishin,O 2571 +94 ½ 1 * 0 1 ½ ½ 1 ½ 1 ½ 1 7.5/11 >4 Khenkin,I 2587 +6 ½ ½ 1 * ½ 0 ½ 1 ½ 0 1 1 6.5/11 34.00 >5 Ftacnik,L 2576 +18 ½ ½ 0 ½ * ½ ½ ½ 1 1 ½ 1 6.5/11 30.50 >6 Movsesian,S 2624 -33 0 0 ½ 1 ½ * 1 ½ 1 0 1 1 6.5/11 30.25 >7 Stohl,I 2550 -18 0 ½ ½ ½ ½ 0 * ½ 1 ½ 1 ½ 5.5/11 25.75 >8 Markos,J 2467 +72 ½ 0 0 0 ½ ½ ½ * 1 1 1 ½ 5.5/11 23.75 >9 Plachetka,J 2441 -35 0 0 ½ ½ 0 0 0 0 * 1 ½ 1 3.5/11 >10 Mrva,Mart 2426 -57 0 0 0 1 0 1 ½ 0 0 * ½ 0 3.0/11 >11 Priehoda,V 2425 -99 0 0 ½ 0 ½ 0 0 0 ½ ½ * ½ 2.5/11 11.50 >12 Tibensky,R 2448 -124 0 0 0 0 0 0 ½ ½ 0 1 ½ * 2.5/11 9.75 > >Average elo: 2533 <=> Category: 12 >gm = 6.60 m = 4.40 > >1) Can someone explain what the +/- numbers after the player ratings mean, how >they're calculated, and what they are called? This is the difference between the players rating and their performance in the tournament. Sutovsky,E performed at a level of 2660 +79 = 2739 in this tournament. How they're calculated I'll leave to someone else. > >2) Can someone explain what the decimal numbers after the X.X/Y at the end stand >for, what they're called, and how they are calculated? For people on an equal score, a calculation is made to tie-break them for the placings. eg. 4 Khenkin,I: (Multiply his score against player 1 by the points player 1 scored) + ((Multiply his score against player 2 by the points player 2 scored) + (Multiply his score against player 3....... ) > >If the calculations are too involved, an explanation isn't necessary- I just >want to know what these things stand for, so I can interpret what the statistics >chessbase generates for my own games mean! > >Thanks to all for any help... Cheers, Tina Long
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