Author: Robert Hyatt
Date: 15:38:48 09/06/02
Go up one level in this thread
On September 06, 2002 at 16:27:22, Dieter Buerssner wrote: >On September 06, 2002 at 16:14:19, Robert Hyatt wrote: > >>>What is the estimated size [of kppkpp]? > >>at least 1000 gigabytes (a terabyte) > >How do you estimate this? > >My simple estimation (ignoring the ep problem, but it should not make a bigger >factor) would be: > >3612 * 48 *47 / 2 * 46 * 45 / 2 > >which would make 4 Gb positions, compressed obviously less. Even 64^6 (taking no >symmetry into account) is "only" 64 gigabytes. > >Regards, >Dieter The threes/fours/fives are 7.5 gigs already. But even more importantly, the 6's are going to blow a byte for scores... So they are going to be twice the size to boot. I already have some compressed 6 piece tables that are > 2.0 gigabytes. We have almost 100 gigs with no pawns done yet, and not all of 3 vs 3 are done yet... much less 4 vs 2, 1 vs 5 and then those pawns... IMHO a terabyte is a lower bound... not upper.
This page took 0 seconds to execute
Last modified: Thu, 15 Apr 21 08:11:13 -0700
Current Computer Chess Club Forums at Talkchess. This site by Sean Mintz.