Author: Arturo Ochoa
Date: 07:50:18 09/09/02
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On September 09, 2002 at 10:04:12, Ed Panek wrote: >long x; >double y; > >y = 2.01; >x = (long)(y * 1000); > > >guess what x equals? ... > >No, not 2010, but 2009 !!!!!!!!!!!!!!! > >Ed Hello: For operations with precision, I use the primitive float instead double when you operate between different types. float y = (float) 2.01; long x; x = (long) (y * 1000); ////////////////////////////////// y = (float) 2.00001; x = (long) (y * 100000); ////////////////////////////////// Here, you get the expected result. Regards, Arturo.
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