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Subject: Re: Couple of chess programming questions

Author: Dann Corbit

Date: 14:08:23 09/10/02

Go up one level in this thread


On September 10, 2002 at 16:18:35, Gian-Carlo Pascutto wrote:

>On September 10, 2002 at 15:35:48, Dann Corbit wrote:
>
>>On September 10, 2002 at 14:19:24, Gian-Carlo Pascutto wrote:
>>
>>>On September 10, 2002 at 13:11:02, Dann Corbit wrote:
>>>
>>>>The MTD(f) algorithm basically does a binary search between two bounds (on
>>>>average -- it might be faster or slower in individual cases).
>>>
>>>MTD(n,f) _as descibred by Plaat_ does not do a binary search.
>>>
>>>It will take a first guess, and then always fail in the same
>>>direction till it converges.
>>
>>Normally, assuming your first guess is a very good one.  The idea is still
>>roughly the same.  Let's suppose that the first guess is exactly right -- then
>>the initial second guess (normally negative infinity)
>
>This is not MTD(n,f). As I already said, you seem to have something
>else in mind.

http://www.cs.vu.nl/~aske/mtdf.htmlhttp://www.cs.vu.nl/~aske/mtdf.html

function MTDF(root : node_type; f : integer; d : integer) : integer;

g := f;
upperbound := +INFINITY;
lowerbound := -INFINITY;
repeat

if g == lowerbound then beta := g + 1 else beta := g;
g := AlphaBetaWithMemory(root, beta - 1, beta, d);
if g < beta then upperbound := g else lowerbound := g;

until lowerbound >= upperbound;
return g;

Since it searches until upperbound and lowerbound converge, evidently, they can
exchange roles.  This is the binary search analog that I am referring to:
"if g < beta then upperbound := g else lowerbound := g;"

I think we are not on the same page for some reason.  Or (more likely) I am
simply not expressing myself clearly.




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